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Mathematics
Problem
Let
f
(
x
)
=
∣
x
−
2
∣
x
−
2
f(x)=\dfrac{|x-2|}{x-2}
f
(
x
)
=
x
−
2
∣
x
−
2∣
for
2
<
x
≤
5
2<x\le 5
2
<
x
≤
5
. The value of
f
(
2
)
f(2)
f
(
2
)
is to be chosen so that
f
f
f
becomes continuous on the closed interval
[
2
,
5
]
[2,5]
[
2
,
5
]
. Which choice makes
f
f
f
continuous? a)
−
1
-1
−
1
b)
1
1
1
c)
0
0
0
d)
2
2
2
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