Let n≥2 be a natural number and f:[0,1]→ℝ be defined by f(x)=n(1−2nx) for 0≤x≤1/(2n); f(x)=2n(2nx−1) for 1/(2n)≤x≤3/(4n); f(x)=4n(1−nx) for 3/(4n)≤x≤1/n; and f(x)=n(nx−1)/(n−1) for 1/n≤x≤1. If n is such that the area bounded by x=0, x=1, y=0 and y=f(x) is 4, then the maximum value of f is