Physics

Problem

Identical charges

(-q)

are placed at each corner of a cube of side

b

then electrical potential energy of charge

(+q)

which is placed at centre of cube will be: (2002) a.

\frac{-4\sqrt{2}q^2}{\pi\epsilon_0 b}

\frac{-8\sqrt{2}q^2}{\pi\epsilon_0 b}

\frac{-4q^2}{\sqrt{3}\pi\epsilon_0 b}

\frac{8\sqrt{2}q^2}{4\pi\epsilon_0 b}