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Mathematics
Mathematics
Problem
For the curve
y
2
=
x
2
+
4
λ
x
y^{2} = x^{2} + 4\lambda x
y
2
=
x
2
+
4
λ
x
with
λ
>
0
\lambda>0
λ
>
0
, the tangent at the point whose
x
x
x
-coordinate is
1
1
1
passes through the fixed point
(
0
,
−
3
)
(0,-3)
(
0
,
−
3
)
. Find the value of
λ
\lambda
λ
. a)
3
10
3\sqrt{10}
3
10
b)
9
2
\dfrac{9}{2}
2
9
c)
9
+
3
10
2
\dfrac{9+3\sqrt{10}}{2}
2
9
+
3
10
d)
3
+
6
2
\dfrac{3+\sqrt{6}}{2}
2
3
+
6
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