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Physics
Physics
Problem
The electric field component of a monochromatic radiation is given by
E
⃗
=
2
E
0
i
^
cos
k
z
cos
ω
t
\vec{E} = 2E_0 \hat{i} \cos kz \cos \omega t
E
=
2
E
0
i
^
cos
k
z
cos
ω
t
Its magnetic field
B
⃗
\vec{B}
B
is then given by: a.
2
E
0
c
j
^
sin
k
z
cos
ω
t
\frac{2E_0}{c} \hat{j} \sin kz \cos \omega t
c
2
E
0
j
^
sin
k
z
cos
ω
t
b.
−
2
E
0
c
j
^
sin
k
z
sin
ω
t
-\frac{2E_0}{c} \hat{j} \sin kz \sin \omega t
−
c
2
E
0
j
^
sin
k
z
sin
ω
t
c.
2
E
0
c
j
^
sin
k
z
sin
ω
t
\frac{2E_0}{c} \hat{j} \sin kz \sin \omega t
c
2
E
0
j
^
sin
k
z
sin
ω
t
d.
2
E
0
c
j
^
cos
k
z
cos
ω
t
\frac{2E_0}{c} \hat{j} \cos kz \cos \omega t
c
2
E
0
j
^
cos
k
z
cos
ω
t
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