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Physics
Physics
Problem
Using the atomic mass data:
1
3
H
:
3.016
u
^{3}_{1}\mathrm H: 3.016\,\text{u}
1
3
H
:
3.016
u
,
1
2
H
:
2.014
u
^{2}_{1}\mathrm H: 2.014\,\text{u}
1
2
H
:
2.014
u
,
2
4
H
e
:
4.003
u
^{4}_{2}\mathrm He: 4.003\,\text{u}
2
4
H
e
:
4.003
u
,
0
1
n
:
1.009
u
^{1}_{0}\mathrm n: 1.009\,\text{u}
0
1
n
:
1.009
u
, calculate the energy released (Q-value) in MeV for the fusion reaction
1
3
H
+
1
2
H
→
2
4
H
e
+
0
1
n
^{3}_{1}\mathrm H + ^{2}_{1}\mathrm H \rightarrow ^{4}_{2}\mathrm He + ^{1}_{0}\mathrm n
1
3
H
+
1
2
H
→
2
4
H
e
+
0
1
n
. (Use
1
u
=
931.5
MeV
/
c
2
1\,\text{u} = 931.5\,\text{MeV}/c^{2}
1
u
=
931.5
MeV
/
c
2
.) a)
20.4
MeV
20.4\,\text{MeV}
20.4
MeV
b)
15.0
MeV
15.0\,\text{MeV}
15.0
MeV
c)
17.6
MeV
17.6\,\text{MeV}
17.6
MeV
d)
13.6
MeV
13.6\,\text{MeV}
13.6
MeV
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