A First Course in Complex Analysis · Problem 39

Consequences of Cauchy's Theorem — Beck, Marchesi, Pixton & Sabalka

Mathematics — Complex Analysis · cauchys-integral-formula

Problem

This exercise gives an alternative proof of Cauchy's Integral Formula (Theorem 4.4.5) that does not depend on Cauchy's Theorem (Theorem 4.3.4). Suppose the region GG is convex; this means that, whenever zz and ww are in GG, the line segment between them is also in GG. Suppose ff is holomorphic in GG, f′f' is continuous, and γ\gamma is a positively oriented, simple, closed, piecewise smooth path, such that ww is inside γ\gamma and γ∼G0\gamma \sim_G 0. (a) Consider the function g:[0,1]→Cg: [0,1] \to \mathbb{C} given by g(t):=∫γf(w+t(z−w))z−w dz.g(t) := \int_{\gamma} \frac{f(w + t(z-w))}{z - w}\, dz. Show that g′=0g' = 0. Hint. Use Theorem A.0.9 (Leibniz's rule) and then find an antiderivative for ∂f∂t(w+t(z−w))\dfrac{\partial f}{\partial t}(w + t(z-w)). (b) Prove Theorem 4.4.5 by evaluating g(0)g(0) and g(1)g(1). (c) Why did we assume GG is convex?

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