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Physics
Physics
Problem
Which of the following correctly gives the relation between the root-mean-square (rms) value
ε
rms
\varepsilon_{\text{rms}}
ε
rms
and the peak value
ε
0
\varepsilon_0
ε
0
of the emf generated by a single-phase alternator? a)
ε
rms
=
2
ε
0
π
\varepsilon_{\text{rms}}=\dfrac{2\varepsilon_0}{\pi}
ε
rms
=
π
2
ε
0
b)
ε
rms
=
ε
0
2
\varepsilon_{\text{rms}}=\varepsilon_0\sqrt{2}
ε
rms
=
ε
0
2
c)
ε
rms
=
ε
0
2
\varepsilon_{\text{rms}}=\dfrac{\varepsilon_0}{\sqrt{2}}
ε
rms
=
2
ε
0
d)
ε
rms
=
ε
0
3
\varepsilon_{\text{rms}}=\dfrac{\varepsilon_0}{\sqrt{3}}
ε
rms
=
3
ε
0
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