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Physics
Physics
Problem
On Venus, a vertical column of mercury (
ρ
=
13
600
kg
m
−
3
\rho = 13\,600\,\text{kg}\,\text{m}^{-3}
ρ
=
13
600
kg
m
−
3
) stands 0.70 m high under the planet’s surface gravity
g
=
8.87
m
s
−
2
g = 8.87\,\text{m}\,\text{s}^{-2}
g
=
8.87
m
s
−
2
. Calculate the gauge pressure corresponding to this column and express the result in atmospheres (
1
atm
=
1.01
×
10
5
Pa
1\,\text{atm} = 1.01 \times 10^{5}\,\text{Pa}
1
atm
=
1.01
×
1
0
5
Pa
).
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