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Mathematics
Mathematics
Problem
The locus of the mid-points of the chords of the circle
x
2
+
y
2
+
4
x
−
6
y
−
12
=
0
x^2 + y^2 + 4x - 6y - 12 = 0
x
2
+
y
2
+
4
x
−
6
y
−
12
=
0
which subtend an angle of
π
3
\frac{\pi}{3}
3
π
radians at its circumference is a.
(
x
+
2
)
2
+
(
y
−
3
)
2
=
6.25
(x+2)^2 + (y-3)^2 = 6.25
(
x
+
2
)
2
+
(
y
−
3
)
2
=
6.25
b.
(
x
−
2
)
2
+
(
y
+
3
)
2
=
6.25
(x-2)^2 + (y+3)^2 = 6.25
(
x
−
2
)
2
+
(
y
+
3
)
2
=
6.25
c.
(
x
+
2
)
2
+
(
y
−
3
)
2
=
18.75
(x+2)^2 + (y-3)^2 = 18.75
(
x
+
2
)
2
+
(
y
−
3
)
2
=
18.75
d.
(
x
+
2
)
2
+
(
y
+
3
)
2
=
18.75
(x+2)^2 + (y+3)^2 = 18.75
(
x
+
2
)
2
+
(
y
+
3
)
2
=
18.75
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