Problem

Problem

If 2x+y+1−f=02x + y + \frac{1}{-f} = 0 is a normal to the parabola y2=−8xy^2 = -8x, then the value of 1−f\frac{1}{-f} is a. −24-24 b. −16-16 c. −8-8 d. 2424

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