Mathematics

Mathematics

Problem

If the sum of the first 20 terms of the series 4.14+3.12+14+4.24+3.22+24+4.34+3.32+34+4.44+3.42+44+…\frac{4.1}{4+3.1^2+1^4} + \frac{4.2}{4+3.2^2+2^4} + \frac{4.3}{4+3.3^2+3^4} + \frac{4.4}{4+3.4^2+4^4} + \dots is mn\frac{m}{n}, where mm and nn are coprime, then m+nm+n is equal to :-

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