Physics

Physics · thermodynamics

Problem

ii. Relative to the far-away surroundings, the pipe's electrostatic potential is φ\varphi. Find the charge QQ of a drop when its radius is rr. Given constants: Problem T2. Kelvin water dropper The following facts about the surface tension may turn out to be useful for this problem. For the molecules of a liquid, the positions at the liquid-air interface are less favourable as compared with the positions in the bulk of the liquid. This interface is described by the so-called surface energy, U=σSU=\sigma S, where SS is the surface area of the interface and σ\sigma is the surface tension coefficient of the liquid. Moreover, two fragments of the liquid surface pull each other with a force F=σlF=\sigma l, where ll is the length of a straight line separating the fragments. <image_1> A long metallic pipe with internal diameter dd is pointing directly downwards. Water is slowly dripping from a nozzle at its lower end, see fig. Water can be considered to be electrically conducting; its surface tension is σ\sigma and its density is ρ\rho. A droplet of radius rr hangs below the nozzle. The radius grows slowly in time until the droplet separates from the nozzle due to the free fall acceleration gg. Always assume that d≪rd \ll r. Part A. Single pipe Context question: i. Find the radius rmax⁡r_{\max } of a drop just before it separates from the nozzle. Context answer: rmax⁡=3σd4ρg3r_{\max }=\sqrt[3]{\frac{3 \sigma d}{4 \rho g}}

Related theory

Browse the problem library