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Problem
Problem
The least positive value of
x
x
x
satisfying
sin
2
2
x
+
4
sin
4
x
−
4
sin
2
x
cos
2
x
4
−
sin
2
2
x
−
4
sin
2
x
=
1
9
\frac{\sin^2 2x + 4\sin^4 x - 4\sin^2 x \cos^2 x}{4 - \sin^2 2x - 4\sin^2 x} = \frac{1}{9}
4
−
s
i
n
2
2
x
−
4
s
i
n
2
x
s
i
n
2
2
x
+
4
s
i
n
4
x
−
4
s
i
n
2
x
c
o
s
2
x
=
9
1
is a.
π
/
3
\pi/3
π
/3
b.
π
/
6
\pi/6
π
/6
c.
2
π
/
3
2\pi/3
2
π
/3
d.
5
π
/
6
5\pi/6
5
π
/6
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