Lebl-Basic-Analysis-I · Problem 4.2.9

The Derivative

Mathematics · lhopital-rule-mvt

Problem

Prove the following version of L'H\^opital's rule. Suppose f:(a,b)→Rf : (a,b) \to \mathbb{R} and g:(a,b)→Rg : (a,b) \to \mathbb{R} are differentiable functions and c∈(a,b)c \in (a,b). Suppose that f(c)=0f(c) = 0, g(c)=0g(c) = 0, g′(x)≠0g'(x) \neq 0 when x≠cx \neq c, and that the limit of f′(x)/g′(x)f'(x)/g'(x) as xx goes to cc exists. Show that lim⁡x→cf(x)g(x)=lim⁡x→cf′(x)g′(x).\lim_{x \to c} \frac{f(x)}{g(x)} = \lim_{x \to c} \frac{f'(x)}{g'(x)}. Compare to Exercise 4.1.15. Note: Before you do anything else, prove that g(x)≠0g(x) \neq 0 when x≠cx \neq c.

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