Physics

Physics

Problem

A simple pendulum has time period T1T_1 . The point of suspension is now moved upward according to the relation y=Kr2y = Kr^2 , ( K=1 m/s2K = 1 \text{ m/s}^2 ) where yy is the vertical displacement. The time period now becomes T2T_2 . The ratio of T12T22\frac{T_1^2}{T_2^2} is (g = 10 m/s210 \text{ m/s}^2 ) a. 5/6 b. 6/5 c. 1 d. 4/5

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