Mathematics

Mathematics

Problem

When 2x3+ax2+bx+62x^3 + ax^2 + bx + 6 is divided by x2−1x^2 - 1, the remainder is 3x+23x + 2. The values of aa and bb respectively are a) (1, −4)(1,\,-4) b) (−4, 1)(-4,\,1) c) (−4, −1)(-4,\,-1) d) (4, −1)(4,\,-1)

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