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Mathematics
Mathematics
Problem
In the given figure,
P
A
⊥
A
B
PA \perp AB
P
A
⊥
A
B
,
Q
B
⊥
A
B
QB \perp AB
QB
⊥
A
B
and
P
A
=
Q
B
PA = QB
P
A
=
QB
.
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