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Problem
Problem
If
A
A
A
and
B
B
B
are acute positive angles satisfying the equations
3
sin
2
A
+
2
sin
2
B
=
1
3 \sin^2 A + 2 \sin^2 B = 1
3
sin
2
A
+
2
sin
2
B
=
1
and
3
sin
2
A
−
2
sin
3
B
=
0
3 \sin 2A - 2 \sin 3B = 0
3
sin
2
A
−
2
sin
3
B
=
0
, then
A
+
2
B
A + 2B
A
+
2
B
is equal to a.
π
4
\frac{\pi}{4}
4
π
b.
π
2
\frac{\pi}{2}
2
π
c.
3
π
4
\frac{3\pi}{4}
4
3
π
d.
2
π
3
\frac{2\pi}{3}
3
2
π
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