Physics

Problem

For an isolated point charge, the electric potential is

+450\,\text{V}

at a distance of

0.15\,\text{m}

and

+225\,\text{V}

at a distance of

0.30\,\text{m}

. Determine the magnitude and sign of the charge. (Take

\dfrac{1}{4\pi\epsilon_{0}}=9\times10^{9}\,\text{N m}^2\!\text{/C}^2

.) a)

+8.4\,\text{nC}

-7.5\,\text{nC}

+7.5\,\text{nC}

+22.5\,\text{nC}