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Chemistry
Chemistry
Problem
For the reaction
R
X
+
O
H
−
⟶
R
O
H
+
X
−
RX + OH^- \longrightarrow ROH + X^-
R
X
+
O
H
−
⟶
R
O
H
+
X
−
at 50°C the rate expression is given as :
rate
=
4.7
×
10
−
5
[
R
X
]
[
O
H
−
]
+
0.24
×
10
−
5
[
R
X
]
\text{rate} = 4.7 \times 10^{-5} [RX][OH^-] + 0.24 \times 10^{-5} [RX]
rate
=
4.7
×
1
0
−
5
[
R
X
]
[
O
H
−
]
+
0.24
×
1
0
−
5
[
R
X
]
what percentage of *RX* reacts by the *S_N2* mechanism when
[
O
H
−
]
=
0.001
M
[OH^-] = 0.001 M
[
O
H
−
]
=
0.001
M
a. 0.192 b. 0.0192 c. 19.2 d. 1.92
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