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Mathematics
Mathematics
Problem
Let
f
f
f
and
g
g
g
be differentiable functions on
R
\mathbb{R}
R
(the set of all real numbers) such that
g
(
1
)
=
2
=
g
′
(
1
)
g(1)=2=g'(1)
g
(
1
)
=
2
=
g
′
(
1
)
and
f
′
(
0
)
=
4
f'(0)=4
f
′
(
0
)
=
4
. If
h
(
x
)
=
f
(
2
x
g
(
x
)
+
cos
(
π
x
)
−
3
)
h(x)=f(2x\,g(x)+\cos(\pi x)-3)
h
(
x
)
=
f
(
2
x
g
(
x
)
+
cos
(
π
x
)
−
3
)
then
h
′
(
1
)
h'(1)
h
′
(
1
)
is equal to (a) 28 (b) 24 (c) 32 (d) 18
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