A closed barrel has as its curved surface the surface obtained by rotating about the x-axis the part of the curve
y=a[2−cosh(x/a)]
lying in the range −b≤x≤b, where b<acosh−12. Show that the total surface area, A, of the barrel is given by
A=πa[9a−8aexp(−b/a)+aexp(−2b/a)−2b].