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Mathematics
Mathematics
Problem
The position of a particle moving along a line is given by
s
(
t
)
=
2
t
3
−
15
t
2
+
36
t
s(t)=2t^{3}-15t^{2}+36t
s
(
t
)
=
2
t
3
−
15
t
2
+
36
t
meters for
0
≤
t
≤
4
0\le t\le4
0
≤
t
≤
4
. At what time during this interval is the particle farthest to the right? a)
t
=
2.5
t=2.5
t
=
2.5
b)
t
=
3
t=3
t
=
3
c)
t
=
4
t=4
t
=
4
d)
t
=
2
t=2
t
=
2
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