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Let
e
y
=
(
1
+
α
+
1
−
α
1
+
α
−
1
−
α
)
e^y=\left(\frac{\sqrt{1+\alpha}+\sqrt{1-\alpha}}{\sqrt{1+\alpha}-\sqrt{1-\alpha}}\right)
e
y
=
(
1
+
α
−
1
−
α
1
+
α
+
1
−
α
)
…
Mathematics
Problem
Let
e
y
=
(
1
+
α
+
1
−
α
1
+
α
−
1
−
α
)
e^y=\left(\frac{\sqrt{1+\alpha}+\sqrt{1-\alpha}}{\sqrt{1+\alpha}-\sqrt{1-\alpha}}\right)
e
y
=
(
1
+
α
−
1
−
α
1
+
α
+
1
−
α
)
and
tan
(
x
2
)
=
1
−
α
1
+
α
\tan\left(\frac{x}{2}\right)=\sqrt{\frac{1-\alpha}{1+\alpha}}
tan
(
2
x
)
=
1
+
α
1
−
α
,
α
∈
[
−
1
,
0
)
∪
(
0
,
1
]
\alpha\in[-1,0)\cup(0,1]
α
∈
[
−
1
,
0
)
∪
(
0
,
1
]
then find
d
y
d
x
∣
x
=
π
3
\frac{dy}{dx}\bigg|_{x=\frac{\pi}{3}}
d
x
d
y
x
=
3
π
.
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