Mathematics

Mathematics

Problem

tan⁡[sec⁡−11+x2]=\tan[\sec^{-1}\sqrt{1+x^2}] = (a) 1x\frac{1}{x} (b) ∣x∣|x| (c) 11+x2\frac{1}{\sqrt{1+x^2}} (d) x1+x2\frac{x}{\sqrt{1+x^2}}

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