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Mathematics
Mathematics
Problem
For the curve
x
=
t
2
,
y
=
3
t
+
1
x=t^{2},\, y=3t+1
x
=
t
2
,
y
=
3
t
+
1
, the tangent is vertical when the parameter
t
t
t
equals: a)
−
1
3
-\dfrac{1}{3}
−
3
1
b)
0
0
0
c)
3
2
\dfrac{3}{2}
2
3
d)
−
1
-1
−
1
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