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Mathematics
Problem
For the differential equation
d
y
d
x
=
sin
x
+
1
\dfrac{dy}{dx}=\sin x+1
d
x
d
y
=
sin
x
+
1
with the initial condition
y
(
0
)
=
4
y(0)=4
y
(
0
)
=
4
, determine the exact value of
y
(
π
2
)
y\!\left(\dfrac{\pi}{2}\right)
y
(
2
π
)
. a)
4
+
π
2
4+\dfrac{\pi}{2}
4
+
2
π
b)
6
+
π
2
6+\dfrac{\pi}{2}
6
+
2
π
c)
5
+
π
2
5+\dfrac{\pi}{2}
5
+
2
π
d)
3
+
π
2
3+\dfrac{\pi}{2}
3
+
2
π
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