Problem

Problem

A particle is projected from ground with velocity 40 m/s40\text{ m/s} at 60∘60^\circ from horizontal. (a) Find the speed when velocity of the particle makes an angle of 37∘37^\circ from horizontal. (b) Find the time for the above situation. (c) Find the vertical height and horizontal distance of the particle from the starting point in the above position. Take g=10 m/s2g=10\text{ m/s}^2.

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