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Problem
Problem
Solve the equation
(
1
−
tan
θ
)
(
1
+
sin
2
θ
)
=
1
+
tan
θ
(1 - \tan \theta)(1 + \sin 2\theta) = 1 + \tan \theta
(
1
−
tan
θ
)
(
1
+
sin
2
θ
)
=
1
+
tan
θ
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