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Mathematics
Problem
∫
log
10
x
d
x
=
\int \log_{10} x \, dx =
∫
lo
g
10
x
d
x
=
(a)
x
log
10
x
+
c
x \log_{10} x + c
x
lo
g
10
x
+
c
(b)
x
(
log
10
x
+
log
10
e
)
+
c
x (\log_{10} x + \log_{10} e) + c
x
(
lo
g
10
x
+
lo
g
10
e
)
+
c
(c)
log
10
x
+
c
\log_{10} x + c
lo
g
10
x
+
c
(d)
x
(
log
10
x
−
log
10
e
)
+
c
x (\log_{10} x - \log_{10} e) + c
x
(
lo
g
10
x
−
lo
g
10
e
)
+
c
(a)
x
log
10
x
+
c
x \log_{10} x + c
x
lo
g
10
x
+
c
(b)
x
(
log
10
x
+
log
10
e
)
+
c
x (\log_{10} x + \log_{10} e) + c
x
(
lo
g
10
x
+
lo
g
10
e
)
+
c
(c)
log
10
x
+
c
\log_{10} x + c
lo
g
10
x
+
c
(d)
x
(
log
10
x
−
log
10
e
)
+
c
x (\log_{10} x - \log_{10} e) + c
x
(
lo
g
10
x
−
lo
g
10
e
)
+
c
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