Mathematics

Mathematics

Problem

If sin⁡y=xsin⁡(a+y)\sin y = x \sin(a + y), then dydx=\frac{dy}{dx} = (a) sin⁡2(a+y)sin⁡(a+2y)\frac{\sin^2(a + y)}{\sin(a + 2y)} (b) sin⁡2(a+y)cos⁡(a+2y)\frac{\sin^2(a + y)}{\cos(a + 2y)} (c) sin⁡2(a+y)sin⁡a\frac{\sin^2(a + y)}{\sin a} (d) sin⁡2(a+y)cos⁡a\frac{\sin^2(a + y)}{\cos a}

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