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Basic Analysis I — Real Analysis
· Problem 1.3.2
Real Numbers — Jiri Lebl
Mathematics — Real Analysis · absolute-value
Problem
Show: a)
max
{
x
,
y
}
=
x
+
y
+
∣
x
−
y
∣
2
\max\{x, y\} = \dfrac{x + y + |x - y|}{2}
max
{
x
,
y
}
=
2
x
+
y
+
∣
x
−
y
∣
b)
min
{
x
,
y
}
=
x
+
y
−
∣
x
−
y
∣
2
\min\{x, y\} = \dfrac{x + y - |x - y|}{2}
min
{
x
,
y
}
=
2
x
+
y
−
∣
x
−
y
∣
Related theory
Absolute Value Inequalities And Intervals
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