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Mathematics
Mathematics
Problem
If
(
a
×
b
)
2
+
(
a
⋅
b
)
2
=
144
(\mathbf{a} \times \mathbf{b})^2 + (\mathbf{a} \cdot \mathbf{b})^2 = 144
(
a
×
b
)
2
+
(
a
⋅
b
)
2
=
144
and
∣
a
∣
=
4
|\mathbf{a}| = 4
∣
a
∣
=
4
, then find the value of
∣
b
∣
|\mathbf{b}|
∣
b
∣
.
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