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Mathematics
Problem
The pressure at a depth
h
h
h
meters in a fluid tank is
P
(
h
)
=
100
h
2
P(h)=100h^{2}
P
(
h
)
=
100
h
2
kilopascals. A probe’s depth changes with time according to
h
(
t
)
=
3
t
−
1
h(t)=3t-1
h
(
t
)
=
3
t
−
1
, where
t
t
t
is in seconds. Determine
d
P
d
t
\dfrac{dP}{dt}
d
t
d
P
at
t
=
0.5
s
t=0.5\text{ s}
t
=
0.5
s
.
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