A parametrically defined curve satisfies the derivative values shown below.
t=−2: x′(t)=0, y′(t)=−3t=0: x′(t)=0, y′(t)=0t=1: x′(t)=2, y′(t)=0t=3: x′(t)=−1, y′(t)=4
Which value of t corresponds to a point where the curve has a vertical tangent?
a) t=1
b) t=−2
c) t=3
d) t=0