Mathematics

Mathematics

Problem

The answers are in Chapter 24. 2. Find dydx\frac{d y}{d x} if x2+3xy2−y3=1x^{2}+3 x y^{2}-y^{3}=1. (A) dydx=−2x−3y26xy−3y2\frac{d y}{d x}=\frac{-2 x-3 y^{2}}{6 x y-3 y^{2}} (B) dydx=2x+3y26xy−3y2\frac{d y}{d x}=\frac{2 x+3 y^{2}}{6 x y-3 y^{2}} (C) dydx=2x+6xy−3y2\frac{d y}{d x}=2 x+6 x y-3 y^{2} (D) dydx=2x−6xy+3y2\frac{d y}{d x}=2 x-6 x y+3 y^{2} (A) dydx=−2x−3y26xy−3y2\frac{d y}{d x}=\frac{-2 x-3 y^{2}}{6 x y-3 y^{2}} (B) dydx=2x+3y26xy−3y2\frac{d y}{d x}=\frac{2 x+3 y^{2}}{6 x y-3 y^{2}} (C) dydx=2x+6xy−3y2\frac{d y}{d x}=2 x+6 x y-3 y^{2} (D) dydx=2x−6xy+3y2\frac{d y}{d x}=2 x-6 x y+3 y^{2}

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