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Physics
Physics
Problem
Two horizontal forces act on a particle:
F
⃗
1
=
12
N
\vec F_1=12\,\text{N}
F
1
=
12
N
due east and
F
⃗
2
=
5
N
\vec F_2=5\,\text{N}
F
2
=
5
N
due north. The magnitude of the least third horizontal force that must be applied to keep the particle in equilibrium is a)
17
N
17\,\text{N}
17
N
b)
7
N
7\,\text{N}
7
N
c)
13
N
13\,\text{N}
13
N
d)
12
N
12\,\text{N}
12
N
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