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Chemistry
Chemistry
Problem
For an elementary reaction at
298
K
298\,\text{K}
298
K
, the activation energy for the forward direction is
72
kJ mol
−
1
72\,\text{kJ mol}^{-1}
72
kJ mol
−
1
and the overall energy change
Δ
E
\Delta E
Δ
E
is
−
18
kJ mol
−
1
-18\,\text{kJ mol}^{-1}
−
18
kJ mol
−
1
. Calculate the activation energy for the reverse reaction, in kJ mol
−
1
^{-1}
−
1
.
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