Mathematics

Mathematics

Problem

Let C1C_1 and C2C_2 be the centres of the circles x2+y2−2x−2y−2=0x^2 + y^2 - 2x - 2y - 2 = 0 and x2+y2−6x−6y+14=0x^2 + y^2 - 6x - 6y + 14 = 0 respectively. If P and Q are the points of intersection of these circles, then the area (in sq. units) of the quadrilateral PC1QC2PC_1QC_2 is : [JEE-MAIN ONLINE-2019] (1) 8 (2) 6 (3) 9 (4) 4

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