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Mathematics
Mathematics
Problem
If
y
x
=
e
y
−
x
y^x = e^{y-x}
y
x
=
e
y
−
x
, then prove that
d
y
d
x
=
(
1
+
log
y
)
2
log
y
\frac{dy}{dx} = \frac{(1+\log y)^2}{\log y}
d
x
d
y
=
l
o
g
y
(
1
+
l
o
g
y
)
2
.
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