Chemistry

Chemistry

Problem

For the reaction, C2H6⟶C2H4+H2\text{C}_2\text{H}_6 \longrightarrow \text{C}_2\text{H}_4 + \text{H}_2 the reaction enthalpy ΔrH=………… kJ mol−1\Delta_r H = \dots\dots\dots\dots \text{ kJ mol}^{-1} (Round off to the nearest integer). [Given : Bond enthalpies in kJ mol−1\text{kJ mol}^{-1} : C—C=347\text{C}—\text{C} = 347 , C=C=611\text{C}=\text{C} = 611 ; C—H=414\text{C}—\text{H} = 414 ; H—H=\text{H}—\text{H} = 436]

Browse the problem library