Chemistry

Chemistry

Problem

The emf of the cell Zn∣Zn2+(0.01 M)∣∣Fe2+(0.001 M)∣Fe\text{Zn} | \text{Zn}^{2+} (0.01 \text{ M}) || \text{Fe}^{2+} (0.001 \text{ M}) | \text{Fe} at 298 K298 \text{ K} is 0.29050.2905, then the value of equilibrium constant for the cell reaction is : a. e0.32/0.0295e^{0.32/0.0295} b. 100.32/0.029510^{0.32/0.0295} c. 100.26/0.029510^{0.26/0.0295} d. 100.32/0.059110^{0.32/0.0591}

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