Problem

Number of atoms in 55.85 gram Fe (at.wt. of Fe = 55.85 g

\text{mol}^{-1}

) is. Twice that 60 g carbon

6.023 \times 10^{22}

6.023 \times 10^{23}

55.85 \times 6.023 \times 10^{23}

a. Twice that 60 g carbon b.

6.023 \times 10^{22}

6.023 \times 10^{23}

55.85 \times 6.023 \times 10^{23}