Physics

Problem

The horizontal range

R

of a projectile launched from ground level with initial speed

v_0

at an angle

\theta_0

to the horizontal is a)

R=\dfrac{v_0^{2}\sin^{2}\theta_0}{2g}

R=\dfrac{v_0^{2}\sin2\theta_0}{2g}

R=\dfrac{v_0^{2}\sin2\theta_0}{g}

R=\dfrac{v_0^{2}\sin\theta_0\cos\theta_0}{g}