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JEE Advanced 2017 Paper 1 Chemistry Q10
Chemistry · Covalent Bonding & Molecular Structure
Problem
The sum of the number of lone pairs of electrons on each central atom in the following species is
[
T
e
B
r
6
]
2
−
[\mathrm{TeBr_6}]^{2-}
[
TeB
r
6
]
2
−
,
[
B
r
F
2
]
+
[\mathrm{BrF_2}]^+
[
Br
F
2
]
+
,
S
N
F
3
\mathrm{SNF_3}
SN
F
3
, and
[
X
e
F
3
]
−
[\mathrm{XeF_3}]^-
[
Xe
F
3
]
−
(Atomic numbers: N = 7, F = 9, S = 16, Br = 35, Te = 52, Xe = 54)
Related theory
Chemical Bonding And Molecular Structure
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