JEE Advanced 2017 Paper 1 Chemistry Q10

Chemistry · Covalent Bonding & Molecular Structure

Problem

The sum of the number of lone pairs of electrons on each central atom in the following species is [TeBr6]2−[\mathrm{TeBr_6}]^{2-}, [BrF2]+[\mathrm{BrF_2}]^+, SNF3\mathrm{SNF_3}, and [XeF3]−[\mathrm{XeF_3}]^- (Atomic numbers: N = 7, F = 9, S = 16, Br = 35, Te = 52, Xe = 54)

Related theory

Browse the problem library