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Mathematics
Mathematics
Problem
If
cos
(
α
+
β
)
+
sin
(
α
−
β
)
=
0
\cos(\alpha + \beta) + \sin(\alpha - \beta) = 0
cos
(
α
+
β
)
+
sin
(
α
−
β
)
=
0
and
tan
β
=
1
2009
\tan \beta = \frac{1}{2009}
tan
β
=
2009
1
; then
tan
3
α
\tan 3\alpha
tan
3
α
is: (a) 2 (b) 1 (c) 3 (d) 4
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