Purcell Problem 2.26

Physics · electromagnetism

Problem

the delta function The Laplacian ∇2\nabla^2 operator is shorthand for the divergence of the gradient. From Appendix F, the gradient of a function that depends only on r equals (∂f/∂r\partial f/\partial r)r^\hat{r}. So we have ∇\nabla(1/r) = −r^/r2-\hat{r}/r^2. The volume integral of ∇2\nabla^2(1/r) is therefore (using the divergence theorem) ∫V∇2(1r)dv=∫V∇⋅∇(1r)dv=∫V∇⋅(−r^r2)dv=−∮Sr^r2⋅da.\int_V \nabla^2 \left(\frac{1}{r}\right) dv = \int_V \nabla \cdot \nabla \left(\frac{1}{r}\right) dv = \int_V \nabla \cdot \left(\frac{-\hat{r}}{r^2}\right) dv = -\oint_S \frac{\hat{r}}{r^2} \cdot da. (12.131) Since ∇2\nabla^2(1/r) = 0 everywhere away from the origin, any volume containing the origin will yield the same integral. Choosing a sphere of radius R gives ∫V∇2(1r)dv=−∮Sr^r2⋅da=−∫1R2da=−4πR2R2=−4π,\int_V \nabla^2 \left(\frac{1}{r}\right) dv = -\oint_S \frac{\hat{r}}{r^2} \cdot da = -\int \frac{1}{R^2} da = -\frac{4\pi R^2}{R^2} = -4\pi, (12.132) as desired. A function that is (1) zero everywhere except at one point and (2) infinite enough at that one point so that it has a nonzero integral, is called a delta function (up to numerical factors).

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