Complex Analysis: Theory and Applications · Problem 7.3.14

Taylor and Laurent Series — Howell & Matthews

Mathematics — Complex Analysis · laurent-series

Problem

Show that cosh⁡ ⁣(z+1z)=∑n=−∞∞anzn\cosh\!\left(z+\dfrac{1}{z}\right) = \displaystyle\sum_{n=-\infty}^{\infty} a_n z^n, where the coefficients can be expressed in the form an=12π∫02πcos⁡nθ cosh⁡(2cos⁡θ) dθ.a_n = \frac{1}{2\pi}\int_0^{2\pi}\cos n\theta\,\cosh(2\cos\theta)\,d\theta. Hint: Let the path of integration be the circle C1+(0)C_1^+(0).

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