Problem

Problem

The value of lim⁡n→∞∑K=1nn−Kn2cos⁡(4Kn)\lim_{n \to \infty} \sum_{K=1}^{n} \frac{n-K}{n^2} \cos \left( \frac{4K}{n} \right) equals a. 14sin⁡4+116cos⁡4−116\frac{1}{4} \sin 4 + \frac{1}{16} \cos 4 - \frac{1}{16} b. 14sin⁡4−116cos⁡4+116\frac{1}{4} \sin 4 - \frac{1}{16} \cos 4 + \frac{1}{16} c. 116(1−sin⁡4)\frac{1}{16} (1 - \sin 4) d. 116(1−cos⁡4)\frac{1}{16} (1 - \cos 4)

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